...tieix 3 53cosx1 0 cosx 0 - - - - - - - 0 fx 0 - - - - 0 - - - - 0 x0 - arccos arccos 2-sin x0 - - - - - - - - 0 04cosx1 0 - - - - - - - 0 fx0 - - - - 0 0 - - - - 0 0VIx0 3 - arccos arccos 53 2fx 0 - - - - - - - 0 - - - - - - 0 fx0 - - - - - 0 0 - - - 0 0fxx 0 23 43 2-2sinx0- - - - - 0 2cosx1 0 - - - - 0 f1x0 - - - - 0 0 - - - 0 6x 0 x1 23 x3 x4 43 x2 2 f1x0 - - - - - - - 0 0 - - - - - - 0 0f2x- - - - -0 0 - - - - -0 0 - - - - fx4 1.88 -0.5 -0.26 0 -0.26 -0.5 1.88 4x 0 2 56 76 32 116 2cosx-3sinx 0 - - - 0 0 - - - - - - - 0 cosx 0 0 f1x0 0 - - - -0 0 - - - 0 - - - 0 x 0 2 32 2sinx0 0 - - - - - - - - - 0cosx 0 - - - - - - - 0 -sinxcosx0 - - - - 0 0 - - - - 0 0x 0 0.91 2 2.22 4.05 32 5.37 2-sinxcosx 0 - - - 0 0 - - - - 0 0 10cos-sinx 0 - - - - 0 0 - - - - - 0 f2x0 - - 0 0 - 0 0 - - 0 0 - - 0 0 VIx 0 6 0.91 2 2.22 56 76 4.05 32 5.37 116 2f1x0 0 - - - 0 - - - - 0 0 - - - - 0 - - - - 0 f2x0 - - - 0 0 - - 0 0 - - - - - 0 0 - - 0 0fx0 0.32 0.18 0 -0.18 -0.32 0 0.32 0.18 0 -0.18 -0.32 0Se obseva ca graficul functiei pe intervalul i0, s este identic cu cel pe intervalul ,2s, in consecinta vom reprezenta functia doar pe intervalul i0, s.6x 0 4 2 34 f1x0 I 0 - - - - - I - - - - - - 0 f2x0 I - - - - - - - - - - - - - I fx0 I- -1 -I 0x 0 4 2 34 54 32 74 2cosx 0 - - - - - - - - - 0 cos2x 0 - - - - - - - 0 0 - - - - - - - - - 0 r I - - - - 0 I - - - - - I 0 - - - - - I VIx 0 4 2 34 54 32 74 2f1x 0 I I 0 - - - I - - - - - - - - - I - - - - 0f2x I - - - - 0 I - - - - - - -I 0 - - - - - I fx1 I- 0 I- -1 -I 0 -I VI x 0 4 2 34 54 32 74 2f1x - - - - - 0 fxI 1 0 0.17 1 2 5.82 I EMBED MSPhotoEd.3 EMBED MSPhotoEd.3 EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3EMBED Equation.3JLx3EGa ,JLNPxzfjpCJBphajUmHnHumHsHa5ajCJ UmHnHuCJCJ 5CJ0CJCJ CJamHsHCJPmHsHCJPBCJaphCJHBCJph5BCJnphajUajBCJnUph
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